Single and combined outcomes
Single outcomes
In this section we will explain and show how to draw a tree diagram. If we flip a coin there are two possible outcomes. There is a \(\frac{\text{1}}{\text{2}}\) chance of getting Heads and a \(\frac{\text{1}}{\text{2}}\) chance of getting Tails. Representing this in a tree diagram would look like this:
If we are rolling a dice the tree diagram would look like this. There is a \(\frac{\text{1}}{\text{6}}\) chance of getting each number.
Combined outcomes
In this section we will use two outcomes to create more interesting games. To make sure we list all possible outcomes of the two events, we use two tools called tree diagrams and twoway tables.
Lets take these two situations mentioned above and combine their outcomes. I.e. we are going to flip the coin once and throw the dice once. We now have a combined event.
When we use more than one object or we repeat an experiment, we call this a compound event. For example, we could get Heads on the coin and a 2 on the dice and we could write this result as H2.
Now we need to use a different process for listing all the possible outcomes.
Tree diagrams of combined outcomes
Let's look at how a tree diagram is used to show combined outcomes.
Example 1: Using a tree diagram for combined outcomes
Question
The tree diagram below shows all the possible outcomes for tossing a coin and then throwing a dice.
 How many possible outcomes are there?
 What is the probability of getting each outcome? Write this probability as a fraction, a decimal and a percentage.
 How many possible outcomes out of the 12 include getting an even number on the dice?
 How many possible outcomes out of 12 include getting Tails and an even number?
 How many possible outcomes out of 12 include getting a 55 on the dice?
Answer
 There are 12 possible outcomes altogether.
 The probability is \(\frac{\text{1}}{\text{12}} = \text{0,08} = \text{8}\%\).
 H2; H4; H6; T2; T4; T6  six of them.
 T2; T4; T6  three possible outcomes.
 H5 and T5  two possible outcomes.
Using a twoway table to show combined outcomes
A twoway table (also known as a contingency table) works in a similar way to a tree diagram. We write the outcomes of one event in rows and the outcomes of the other event in columns.
For example, this table shows all the possible combinations for tossing a coin twice.
H 
T 

H 
H, H 
H, T 
T 
T, H 
T, T 
So each block in the table will show a possible outcome of the combined events. Let's look at a worked example to understand this better.
Example 2: Using a twoway table for combined outcomes
Question
 Draw up a twoway table to show all the possible outcomes for tossing a red dice and a blue dice.
 How many possible outcomes are there?
 Now answer the following:
 What is the chance of rolling a 31 on the blue dice (and any number on the red dice)?
Write the probability of getting a 5 on the blue dice as a:
 fraction.
 decimal fraction (round off your answer to 2 decimal places).
 percentage (round off your answer to 2 decimal places).
 What is the chance of rolling a 4 on the red dice and a 2 on the blue dice?
 What is the chance, in a single roll of both dice, of you getting a 1 and a 2 of either colour?
Answer
 For tossing a red dice and a blue dice we would have:
Table 2 Blue/Red
R1
R2
R3
R4
R5
R6
B1
(B1; R1)
(B1; R2)
(B1; R3)
(B1; R4)
(B1; R5)
(B1; R6)
B2
(B2; R1)
(B2; R2)
(B2;R3)
(B2; R4)
(B2; R5)
(B2; R6)
B3
(B3; R1)
(B3; R2)
(B3; R3)
(B3; R4)
(B3; R5)
(B3; R6)
B4
(B4; R1)
(B4; R2)
(B4; R3)
(B4; R4)
(B4; R5)
(B4; R6)
B5
(B5; R1)
(B5; R2)
(B5; R3)
(B5; R4)
(B5; R5)
(B5; R6)
B6
(B6; R1)
(B6; R2)
(B6; R3)
(B6; R4)
(B6; R5)
(B6; R6)
So, for example, (B1; R3) represents rolling a 1 on the blue dice and a 3 on the red dice.
 There are 36 possible outcomes.

 The chance is 1 in 6 or \(\frac{\text{1}}{\text{6}}\).

 \(\frac{\text{1}}{\text{6}}\)
 0,17
 16,67%
 There is only one block on the table for this: (B2; R4). so there is a 1 in 36 chance of this outcome.
 To get a 1 and a 2: could be (B1; R2) or (B2; R2), so there are two possible outcomes and hence a 2 in 36 chance. This simplifies to 1 in 18 or \(\frac{\text{1}}{\text{18}}\).
Exercise 1: Calculating combined outcomes
Look at the table given for all the possible outcomes for tossing two coins.
H 
T 

H 
H, H 
H, T 
T 
T, H 
T, T 

How many possible outcomes are there altogether?

How many possible outcomes are there for getting two Heads (H; H)?

What is the probability of getting two Heads?

Is the probability of getting two Heads the same as the probability of getting two Tails?

How many possible outcomes are there for getting one Heads and one Tails, in any order?

Is the probability of getting one Heads and one Tails greater or smaller than the probability of getting two Heads? Explain your answer.
Four possible outcomes.
One possible outcome.
1 in 4 or \(\frac{\text{1}}{\text{4}}\)
Yes.
There are two ways of getting this: H; T or T; H.
It is twice as likely to get one Heads and one Tails, because there are two possible ways of getting this and only one way of getting H; H.
A bag contains 5 balls: 2 red (R) and 3 blue (B). In a game of chance, a learner takes a ball out of the bag without looking, notes down the colour, and then puts it back into the bag. The learner then takes out another ball, notes down the colour and puts it back into the bag.
The twoway table shows all of the possible outcomes for this game.
R 
R 
B 
B 
B 

R 
R; R 
R; R 
B; R 
B; R 
B; R 
R 
R; R 
R; R 
B; R 
B; R 
B; R 
B 
R; B 
R; B 
B; B 
B; B 
B; B 
B 
R; B 
R; B 
B; B 
B; B 
B; B 
B 
R; B 
R; B 
B; B 
B; B 
B; B 

How many possible outcomes are there?

How many of the events represent getting R and then B?

Use your list to say what the probability of getting R and then B is.

What is the probability of drawing blue twice?
25
6
\(\frac{\text{6}}{\text{25}}\)
There are 9 possible outcomes out of 25, so the probability is \(\frac{\text{9}}{\text{25}}\).
In a game of chance, learners toss two coins, a R 1 coin and a R 2 coin.
 Draw up a twoway table to show all the possible outcomes.
 How many possible outcomes are there altogether?
 How many of the events are two Heads (H; H)?
 In how many of the events is there only one Heads?
 How many of the events are two Tails (T; T)?
H 
T 

H 
H; H 
T; H 
T 
H; T 
T; T 
 There are four possible outcomes.
 One of the outcomes is (H; H).
 Two of the outcomes have one H only.
 One of the outcomes is (T; T).